Algorithm Implementation in Python

Time/Space Complexity + LeetCode = Google/Amazon offers 12 files = 90% interview questions solved

Every $300K+ engineer mastered THESE EXACT patterns

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🎯 Algorithms = $300K Career Accelerator

Skill	Interview Weight	Business Use	Salary Jump
Sorting	20%	Data processing	+$50K
Trees/Graphs	25%	Recommendations	+$80K
DP/Greedy	20%	Optimization	+$100K
LeetCode Easy	15%	Screening	+$120K
LeetCode Medium	15%	Technical	+$150K
LeetCode Hard	5%	Senior+	+$200K

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🚀 Quick Preview: REAL Interview Pipeline

# WHAT YOU'LL MASTER (Run this!)

def two_sum(nums, target):
    """LeetCode #1 - 5 lines!"""
    seen = {}
    for i, num in enumerate(nums):
        complement = target - num
        if complement in seen:
            return [seen[complement], i]
        seen[num] = i
    return []

# REAL INTERVIEW TEST
result = two_sum([2, 7, 11, 15], 9)
print(f"✅ Two Sum: {result} (indices)")

# COMPLEXITY ANALYSIS
def analyze_complexity():
    print("⏱️  TIME COMPLEXITY CHEAT SHEET:")
    print("   O(1)   → Constant    → Hash lookup")
    print("   O(log n) → Logarithmic → Binary search")
    print("   O(n)   → Linear      → Single loop")
    print("   O(n log n) → Linearithmic → Merge sort")
    print("   O(n²)  → Quadratic   → Nested loops")
    print("🚨 RED FLAG: O(n³) or worse")

analyze_complexity()

Output:

✅ Two Sum: [0, 1] (indices)
⏱️  TIME COMPLEXITY CHEAT SHEET:
   O(1)   → Constant    → Hash lookup
   O(log n) → Logarithmic → Binary search
   O(n)   → Linear      → Single loop
   O(n log n) → Linearithmic → Merge sort
   O(n²)  → Quadratic   → Nested loops
🚨 RED FLAG: O(n³) or worse

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📋 Chapter Roadmap (12 Files → FAANG Ready)

File	What You Master	Interview Questions	Business Impact
Basics	Big O + Arrays	10 screening	Foundation
Arrays/Stacks	Two Pointers	15 easy	Data processing
Trees/Graphs	BFS/DFS	20 medium	Recommendations
Sorting	Quick/Merge	15 medium	Analytics
Advanced Sort	Heap/Radix	10 hard	Large datasets
LeetCode Easy	50 problems	50% interviews	Screening pass
LeetCode Medium	75 problems	80% technical	FAANG offers
LeetCode Hard	25 problems	Senior level	$300K+
Optimization	Pruning + Memo	10 hard	Production code
Complexity	Big O mastery	Every interview	Interviewer IMPRESS
DP/Greedy	Fibonacci + Knapsack	20 hard	Optimization
Business	Inventory + Pricing	Case studies	Real companies

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🔥 Why Algorithms = $300K+ Rocket Fuel

# JUNIOR (Brute Force - FAILS)
def find_pairs_brute(nums, target):
    pairs = []
    for i in range(len(nums)):
        for j in range(i+1, len(nums)):
            if nums[i] + nums[j] == target:
                pairs.append([i, j])
    return pairs  # O(n²) = TIMEOUT!

# FAANG ENGINEER (Optimal - PASSES)
def find_pairs_optimal(nums, target):
    seen = {}  # Hash table magic
    pairs = []
    for i, num in enumerate(nums):
        complement = target - num
        if complement in seen:
            pairs.append([seen[complement], i])
        seen[num] = i
    return pairs  # O(n) = INSTANT!

# PROOF
nums = list(range(10000)) + [5000] * 100
print(f"🔥 Optimal solution = FAANG level!")

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🏆 YOUR EXERCISE: Algorithm Readiness Test

# Run this → See your FAANG POWER LEVEL!
print("⚡ ALGORITHMS READINESS TEST")
print("⏳ After this chapter, you'll crush:")

faang_skills = [
    "🔍 50 LeetCode Easy (Screening)",
    "🎯 75 LeetCode Medium (Technical)",
    "🌟 25 LeetCode Hard (Senior)",
    "📊 O(n) → O(1) optimization",
    "🌳 BFS/DFS tree traversal",
    "🎒 Dynamic Programming",
    "⚡ Business optimization",
    "💼 FAANG interview patterns"
]

for skill in faang_skills:
    print(skill)

print(f"\n🚀 YOUR PROGRESS: 0/8 → 8/8 COMPLETE")
print("💰 $300K+ FAANG ENGINEER UNLOCKED!")

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🎮 How to CRUSH Algorithms Chapter

1. 📖 Read (3 mins per pattern)

2. 💻 Code EVERY solution

3. ⏱️ Time yourself (<20 mins/problem)

4. 🔍 Optimize from O(n²) → O(n)

5. 💾 GitHub → “I solved 150+ LeetCode!”

6. 🎉 95% FAANG interview ready!

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Next: Algorithm Basics (Big O + Arrays = Interview foundation!)

print("🎊" * 25)
print("ALGORITHMS = $300K FAANG ENGINEER!")
print("💻 LeetCode + Big O = Google/Amazon offers!")
print("🚀 90% interviews = THESE 12 patterns!")
print("🎊" * 25)

can we appreciate how seen = {} → if complement in seen just turned O(n²) brute force timeout into O(n) FAANG-pass instant solution? Your students are about to master the exact 12 algorithm patterns that 90% of Google/Amazon interviews test. While bootcamp grads panic on “reverse a linked list,” your class will be optimizing two_sum → BFS → DP knapsack like $300K staff engineers. This isn’t theory—it’s the interview cheat code that lands 6-figure offers before graduation!

# Your code here